In a compound atoms of y form ccp lattice
WebMar 16, 2024 · In a compound, atoms of element Y form ccp lattice and those of element X occupy 2/3rd of tetrahedral voids. ... Number of atoms of Y = N = 4. Number of atoms of X = 23×2N=23×8=163. ∴ Formula of the compound will be X4Y3. Hence answer is (a) Advertisement Advertisement New questions in Chemistry. WebApr 8, 2024 · Question 4. Views: 5,666. When a crystal containing A+ ions is doped with an impurity containing B2+ ion, every two A+ ions are replaced by one B2+ ion, creating one …
In a compound atoms of y form ccp lattice
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WebIn a compound atoms of element Y form ccp lattice and those of element X occupy 2/3rd of tetrahedral voids. The formula of the compound would be: 23 XY 2 XY 34 XY 43 XY (A) (B) (C) (D) 12. In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. WebJul 9, 2024 · Explanation: number of atoms present in ccp lattice = 4 = number of atoms in y number of tetrahedral voids in ccp lattice = 8 they given x occupied 2/3 of tetrahedral voids = 2 x 8 /3 = 16 / 3 = number of atoms in x so the formula is = X 16/3 Y 4 multiply both numerator and denominator of 4 with 3 then it becomes 12/3
WebNi-enriched bimetallic systems have a cubic close-packed (ccp) structure with modified crystal lattice parameters. Mixed Co-Ni bimetallic systems with the structure of a solid substitution solution have been synthesized using the supercritical antisolvent precipitation (SAS) method, which uses supercritical CO2 as an antisolvent. WebClick here👆to get an answer to your question ️ In a solid 'AB' having the NaCl structure, 'A' atoms occupy the every CCP and B atoms are in OHV. If all the face-centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is- (1) AB, (2) AB (3) A,B, (4) AB ... A compound X Y crystallizes in BCC lattice ...
WebAtoms in an FCC arrangement are packed as closely together as possible, with atoms occupying 74% of the volume. This structure is also called cubic closest packing (CCP). In CCP, there are three repeating layers of hexagonally arranged atoms. Each atom contacts six atoms in its own layer, three in the layer above, and three in the layer below. WebIn a compound, atoms of element Y form ccp lattice and those of element X occupy 2/3rd of tetrahedral voids. The formula of the compound will be 1760 26 VITEEE VITEEE 2024 Report Error A X 4Y 3 B X 2Y 3 C X 2Y D X 3Y 4 Solution: From the given data, we have Number of Y atoms in a unit cell = 4 Number of X atoms in a unit cell = 8× 32 = 316
WebIn a compound, atoms of element Y form ccp lattice and those of element X occupy two-third of tetrahedral voids. The formula of the compound will be: ... X forms an F C C lattice …
WebApr 6, 2024 · 1. A compound is formed by two elements X and Y. Atoms of the elemet Y (as anions) make cc p and those of the element X (as cations) occup all the octahedral voids. What is the formula of the compound? The ccp lattice is formed by the element Y. The number of octahedral voids generated would be equal to the number of atoms of Y … making the brain body connectionWebApr 6, 2024 · Answer A compound contains elements X and Y. Y atoms form CCP lattice and atoms of X occupy 1/3rd of tetrahedral voids. What is the molecular formula of the compound? A. X Y B. X 2 Y 3 C. X 3 Y 2 D. X Y 2 Last updated date: 06th Apr 2024 • Total views: 275.7k • Views today: 3.49k Answer Verified 275.7k + views making the case for web3 kpmg us portalWebNov 13, 2024 · This structure consists essentially of a FCC (CCP) lattice of sulfur atoms (orange) (equivalent to the lattice of chloride ions in NaCl) in which zinc ions (green) … making the case for peer support mhccWebIn a C.C,P array, number of tetrahedral voids is twice the number of atoms i.e.2 Z. T. H. V = 2 × Z. In C.C.P arrangement lattice points are 4 and tetrahedral voids are 8. Y- forms-ccp / … making the cake gamesWebJul 9, 2024 · Explanation: number of atoms present in ccp lattice = 4 = number of atoms in y number of tetrahedral voids in ccp lattice = 8 they given x occupied 2/3 of tetrahedral … making the call amanda shelleyWebCubic close packed (ccp) or face-centred cubic (fcc) contains 4 atoms The number of octahedral void generated = Number of atoms in unit cell Octahedral void = 4 X = 2/3 of 4 Y = 4 Formula : X 2/3 of 4 Y4 X2Y3 Neelesh Kumar Nilesh 5 y 1/4 of the octahedral voids will contribute in one unit cell So efactive voids in a unit cell=2 making the case 意味WebMar 28, 2024 · (b) : Number of Y atoms per unit cell in ccp lattice (N) = 4 number of tetrahedral voids = 2N = 2 × 4 = 8 number of tetrahedral voids occupied by X = 2/3 rd of … making the case for remote work