Or ax 1234h or 0ffh

WebMOV AX, [BX] ; Suppose the register BX contains 4895H, then the contents ; 4895H are moved to AX ADD CX, {BX} Based addressing mode In this addressing mode, the offset … WebTranscribed Image Text: Q2) if DS-3456H,SS-234AH, IP ADFCH Mov [2345H], 5675H Mov AX, 1234H ADD AX, [2345H] The final value of AX is A) 3579H b) 68A9H C) 3579D d) 1234H …

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WebEngineering Computer Engineering نقطة واحدة let AX=1235H,SS=1233H and SP=1234H and after the execution POP AX the SP is 1234H O 1238H 1236H 1232H O نقطة واحدة after … WebExample: MOV AL, 0FFh DAS RET ; AL = 0FFh (-1) ; AL = 99h, CF = 1. CZSOPA rrrrrr. Decrement. Algorithm: operand = operand - 1 Example: ... Example: MOV AX, 1234h PUSH AX POP DX ; DX = 1234h RET 8086 instructions. Page 41 of 53. CZSOPA unchanged. Push all general purpose registers AX, CX, DX, BX, SP, BP, SI, DI in the stack. Original value of SP … ct makerspace https://elitefitnessbemidji.com

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Webin the al register to the bl register, given ax =1234h and 3. assembly language instructions. (Total, P, Q and R are one byte long variables and are positive numbers). Total =P-Q+R 4. Determine if the following instructions are legal or not. This problem has been solved! Webanswer bank (DX=FFFFh, AX=80C0h / shl ebx, 3 / shl ebx, 5) 18. What will be the hexadecimal values of DX and AX after the following instructions have executed? mov ax, 3456h mov … ct make abo

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Or ax 1234h or 0ffh

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WebMar 26, 2024 · 1. @Linux The answer is FF00h: AL is incremented and wraps around from FFh to 00h, and AH is unchanged at FFh. Note that the "low", i.e. least-significant bits are written on the right. So for instance when AX = 1234h, you have AH = 12h and AL = 34h. … Weba. mov ax，12h b. mov ax，[1234h] c. mov ds：[1234h]，12h d. mov al，ds：[1234h] 5. 下面源程序语句中，_____包含有寄存器寻址方式。 ... and bx，0ffh and bh，[bx] 上述指令序列运行后，bx的内容是（）( b ) a. 0305h ( bcd ) a. mov al，00 b. and al，00 c. xor al，al d. sub al，al 10. 下面可以形成 ...

Or ax 1234h or 0ffh

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WebStudy with Quizlet and memorize flashcards containing terms like 21. The following statement will assemble without errors: mov WORD PTR [eax], 1234h, 22. The following … WebMOV AX,[BX+DI+1234H] 100010 D W MOD REG R/M Displacement Opcode: 100010 D: 1 Must be 1, dest AX specified by REG W: 1 16 bit transfer MOD: 10 16-bit displacement REG: 000 AX R/M: 001 [BX+DI+DISP] Machine instruction is: 1000 1011 1000 0001 0011 0100 0001 0010 8 B 8 1 3 4 1 2.

Webmov ax,7FFFh add ax,2 ; SF = 1 ; Carry flag example: mov al,0FFh add al,1 ; CF = 1, AL = 00 ; Overflow flag example: mov al,+127 add al,1 ; OF = 1 mov al,-128 sub al,1 ; OF = 1 exit main ENDP END main Programming Exercises 1. Indicate whether or not each of the following instructions is valid. a. add ax,bx b. add dx,bl WebFeb 4, 2024 · (2)将存储单元 3000h 和内容送至 4000h 单元。 (3)将累加器 aX 与寄存器 cx 中的内容对调. 答案： （1)mov aX， 1234H Mov ds, ax movAx, [3000H] mov [4000H], ax xchgax, cx 12.编程：将数据段中以 Bx 为偏移地址的连续 单元的内容颠倒过来。

WebDec 31, 2024 · This instruction does more or less the opposite of MOV AX, [BX]: It writes data to memory. This time, the data in the register BX is written to the memory specified by the registers DS and AX. Because on x86 systems the low byte of some data is stored in the first byte and the high byte is stored in the second byte, the value 1234h would be ... WebORG 100h LEA AX, m RET m DW 1234h END AX is set to: 0104h. LEA instruction takes 3 bytes, RET takes 1 byte, we start at 100h, so the address of 'm' is 104h. LES REG, memory Load memory double word into word register and ES. Algorithm: REG = first word; ES = second word; Example: ORG 100h LES AX, m RET m DW 1234h DW 5678h END AX is set …

Webmov ax,dividendLow cwd; sign-extend dividend mov bx,divisor idiv bx (7.4.7 p8) What will be the contents of AX and DX after the following operation? mov dx,0 mov ax,222h mov cx,100h mul cx Ans.: DX = 0002h, AX = 2200h. (7.4.7 p9) What will be the contents of AX after the following operation? mov ax,63h mov bl,10h div bl Ans.: AX = 0306h.

Web.data myByte BYTE 0FFh, 0 .code mov al,myByte ; AL = mov ah, [myByte+1] ; AH = AL = FFh AH = 00h .data var1 DWORD 10000h var2 DWORD 20000h .code ; ---EAX--- mov eax,var1 ; a.) add eax,var2 ; b.) add ax,0FFFFh ; c.) add eax,1 ; d.) sub ax,1 ; e.) a.) 00010000h b.) 00030000h c.) 0003FFFFh d.) 00040000h e.) 0004FFFFh Sets with similar terms ctm alberton locationWebmov ax,00FFh inc ax ; AX = 0100h mov ax,00FFh inc al ; AX = 0000h Show the value of the destination operand after each of the following instructions executes: .data myByte BYTE … ct make a wishWeb8. (5 points) Write a short sequence of instructions to store the contents of the CX register at theword memory location contained in CX. Thus if CX contains 1234h, the number 1234h will be stored at locations DS:1234h and DS:1235h in memory. mov bx,cx mov [bx],cx mov bx , cx mov [ bx ] , cx earthquake facts for kids ks2WebJZ JNC JP JA JGE JLE Hand assemble the following codes: MOV BX, AX MOV BX, 01234H MOV BX [BP] MOV [SI+5] BX MOV [BX+SI], AL MOV AH, XYZ; Assume that XYZ is located … earthquake fault bay areaWebIf AX-1234H and DX- 20FFH, list the sum and the contents of each flag register bit (C, S, and Z) after the ADD AX, DX instruction executes. 2. This problem has been solved! earthquake fault lines in jerusalemWeb解答：（1）指令oR AX,1234H oR 0FFH 中的第一个oR 是指令系统中的“或”指令，而 第二个oR 是表达式中表示逻辑“或”关系的。（2）指令oR AX,1234H oR 0FFH 中的第一个 . 26 . oR … earthquake fault lines in mississippiWebThe instruction, MOV AX, 1234H is an example of register addressing mode direct addressing mode immediate addressing mode based indexed addressing mode. … earthquake fault line along mississippi river